3.2.56 \(\int \frac {x^5 (a+b \text {csch}^{-1}(c x))}{(d+e x^2)^{5/2}} \, dx\) [156]
Optimal. Leaf size=251 \[ \frac {b c d x \sqrt {-1-c^2 x^2}}{3 \left (c^2 d-e\right ) e^2 \sqrt {-c^2 x^2} \sqrt {d+e x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}+\frac {b x \text {ArcTan}\left (\frac {\sqrt {e} \sqrt {-1-c^2 x^2}}{c \sqrt {d+e x^2}}\right )}{e^{5/2} \sqrt {-c^2 x^2}}+\frac {8 b c \sqrt {d} x \text {ArcTan}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {-1-c^2 x^2}}\right )}{3 e^3 \sqrt {-c^2 x^2}} \]
[Out]
-1/3*d^2*(a+b*arccsch(c*x))/e^3/(e*x^2+d)^(3/2)+b*x*arctan(e^(1/2)*(-c^2*x^2-1)^(1/2)/c/(e*x^2+d)^(1/2))/e^(5/
2)/(-c^2*x^2)^(1/2)+8/3*b*c*x*arctan((e*x^2+d)^(1/2)/d^(1/2)/(-c^2*x^2-1)^(1/2))*d^(1/2)/e^3/(-c^2*x^2)^(1/2)+
2*d*(a+b*arccsch(c*x))/e^3/(e*x^2+d)^(1/2)+1/3*b*c*d*x*(-c^2*x^2-1)^(1/2)/(c^2*d-e)/e^2/(-c^2*x^2)^(1/2)/(e*x^
2+d)^(1/2)+(a+b*arccsch(c*x))*(e*x^2+d)^(1/2)/e^3
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Rubi [A]
time = 0.85, antiderivative size = 251, normalized size of antiderivative = 1.00, number of steps
used = 10, number of rules used = 11, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.478, Rules used = {272, 45,
6437, 12, 1628, 163, 65, 223, 209, 95, 210} \begin {gather*} -\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}+\frac {b x \text {ArcTan}\left (\frac {\sqrt {e} \sqrt {-c^2 x^2-1}}{c \sqrt {d+e x^2}}\right )}{e^{5/2} \sqrt {-c^2 x^2}}+\frac {8 b c \sqrt {d} x \text {ArcTan}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {-c^2 x^2-1}}\right )}{3 e^3 \sqrt {-c^2 x^2}}+\frac {b c d x \sqrt {-c^2 x^2-1}}{3 e^2 \sqrt {-c^2 x^2} \left (c^2 d-e\right ) \sqrt {d+e x^2}} \end {gather*}
Antiderivative was successfully verified.
[In]
Int[(x^5*(a + b*ArcCsch[c*x]))/(d + e*x^2)^(5/2),x]
[Out]
(b*c*d*x*Sqrt[-1 - c^2*x^2])/(3*(c^2*d - e)*e^2*Sqrt[-(c^2*x^2)]*Sqrt[d + e*x^2]) - (d^2*(a + b*ArcCsch[c*x]))
/(3*e^3*(d + e*x^2)^(3/2)) + (2*d*(a + b*ArcCsch[c*x]))/(e^3*Sqrt[d + e*x^2]) + (Sqrt[d + e*x^2]*(a + b*ArcCsc
h[c*x]))/e^3 + (b*x*ArcTan[(Sqrt[e]*Sqrt[-1 - c^2*x^2])/(c*Sqrt[d + e*x^2])])/(e^(5/2)*Sqrt[-(c^2*x^2)]) + (8*
b*c*Sqrt[d]*x*ArcTan[Sqrt[d + e*x^2]/(Sqrt[d]*Sqrt[-1 - c^2*x^2])])/(3*e^3*Sqrt[-(c^2*x^2)])
Rule 12
Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] && !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]
Rule 45
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])
Rule 65
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]
Rule 95
Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]
Rule 163
Int[(((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/((a_.) + (b_.)*(x_)), x_Symbol]
:> Dist[h/b, Int[(c + d*x)^n*(e + f*x)^p, x], x] + Dist[(b*g - a*h)/b, Int[(c + d*x)^n*((e + f*x)^p/(a + b*x)
), x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x]
Rule 209
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*ArcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])
Rule 210
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])
Rule 223
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] && !GtQ[a, 0]
Rule 272
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]
Rule 1628
Int[(Px_)*((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> With[{
Qx = PolynomialQuotient[Px, a + b*x, x], R = PolynomialRemainder[Px, a + b*x, x]}, Simp[b*R*(a + b*x)^(m + 1)*
(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e
- a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*ExpandToSum[(m + 1)*(b*c - a*d)*(b*e - a*f)*Qx + a*d*f
*R*(m + 1) - b*R*(d*e*(m + n + 2) + c*f*(m + p + 2)) - b*d*f*R*(m + n + p + 3)*x, x], x], x]] /; FreeQ[{a, b,
c, d, e, f, n, p}, x] && PolyQ[Px, x] && LtQ[m, -1] && IntegersQ[2*m, 2*n, 2*p]
Rule 6437
Int[((a_.) + ArcCsch[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_.)*((d_.) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> With[{u
= IntHide[(f*x)^m*(d + e*x^2)^p, x]}, Dist[a + b*ArcCsch[c*x], u, x] - Dist[b*c*(x/Sqrt[(-c^2)*x^2]), Int[Simp
lifyIntegrand[u/(x*Sqrt[-1 - c^2*x^2]), x], x], x]] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && ((IGtQ[p, 0] &&
!(ILtQ[(m - 1)/2, 0] && GtQ[m + 2*p + 3, 0])) || (IGtQ[(m + 1)/2, 0] && !(ILtQ[p, 0] && GtQ[m + 2*p + 3, 0]))
|| (ILtQ[(m + 2*p + 1)/2, 0] && !ILtQ[(m - 1)/2, 0]))
Rubi steps
\begin {align*} \int \frac {x^5 \left (a+b \text {csch}^{-1}(c x)\right )}{\left (d+e x^2\right )^{5/2}} \, dx &=-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}-\frac {(b c x) \int \frac {8 d^2+12 d e x^2+3 e^2 x^4}{3 e^3 x \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}} \, dx}{\sqrt {-c^2 x^2}}\\ &=-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}-\frac {(b c x) \int \frac {8 d^2+12 d e x^2+3 e^2 x^4}{x \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}} \, dx}{3 e^3 \sqrt {-c^2 x^2}}\\ &=-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}-\frac {(b c x) \text {Subst}\left (\int \frac {8 d^2+12 d e x+3 e^2 x^2}{x \sqrt {-1-c^2 x} (d+e x)^{3/2}} \, dx,x,x^2\right )}{6 e^3 \sqrt {-c^2 x^2}}\\ &=\frac {b c d x \sqrt {-1-c^2 x^2}}{3 \left (c^2 d-e\right ) e^2 \sqrt {-c^2 x^2} \sqrt {d+e x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}-\frac {(b c x) \text {Subst}\left (\int \frac {4 d^2 \left (c^2 d-e\right )+\frac {3}{2} d \left (c^2 d-e\right ) e x}{x \sqrt {-1-c^2 x} \sqrt {d+e x}} \, dx,x,x^2\right )}{3 d \left (c^2 d-e\right ) e^3 \sqrt {-c^2 x^2}}\\ &=\frac {b c d x \sqrt {-1-c^2 x^2}}{3 \left (c^2 d-e\right ) e^2 \sqrt {-c^2 x^2} \sqrt {d+e x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}-\frac {(4 b c d x) \text {Subst}\left (\int \frac {1}{x \sqrt {-1-c^2 x} \sqrt {d+e x}} \, dx,x,x^2\right )}{3 e^3 \sqrt {-c^2 x^2}}-\frac {(b c x) \text {Subst}\left (\int \frac {1}{\sqrt {-1-c^2 x} \sqrt {d+e x}} \, dx,x,x^2\right )}{2 e^2 \sqrt {-c^2 x^2}}\\ &=\frac {b c d x \sqrt {-1-c^2 x^2}}{3 \left (c^2 d-e\right ) e^2 \sqrt {-c^2 x^2} \sqrt {d+e x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}-\frac {(8 b c d x) \text {Subst}\left (\int \frac {1}{-d-x^2} \, dx,x,\frac {\sqrt {d+e x^2}}{\sqrt {-1-c^2 x^2}}\right )}{3 e^3 \sqrt {-c^2 x^2}}+\frac {(b x) \text {Subst}\left (\int \frac {1}{\sqrt {d-\frac {e}{c^2}-\frac {e x^2}{c^2}}} \, dx,x,\sqrt {-1-c^2 x^2}\right )}{c e^2 \sqrt {-c^2 x^2}}\\ &=\frac {b c d x \sqrt {-1-c^2 x^2}}{3 \left (c^2 d-e\right ) e^2 \sqrt {-c^2 x^2} \sqrt {d+e x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}+\frac {8 b c \sqrt {d} x \tan ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {-1-c^2 x^2}}\right )}{3 e^3 \sqrt {-c^2 x^2}}+\frac {(b x) \text {Subst}\left (\int \frac {1}{1+\frac {e x^2}{c^2}} \, dx,x,\frac {\sqrt {-1-c^2 x^2}}{\sqrt {d+e x^2}}\right )}{c e^2 \sqrt {-c^2 x^2}}\\ &=\frac {b c d x \sqrt {-1-c^2 x^2}}{3 \left (c^2 d-e\right ) e^2 \sqrt {-c^2 x^2} \sqrt {d+e x^2}}-\frac {d^2 \left (a+b \text {csch}^{-1}(c x)\right )}{3 e^3 \left (d+e x^2\right )^{3/2}}+\frac {2 d \left (a+b \text {csch}^{-1}(c x)\right )}{e^3 \sqrt {d+e x^2}}+\frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{e^3}+\frac {b x \tan ^{-1}\left (\frac {\sqrt {e} \sqrt {-1-c^2 x^2}}{c \sqrt {d+e x^2}}\right )}{e^{5/2} \sqrt {-c^2 x^2}}+\frac {8 b c \sqrt {d} x \tan ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {-1-c^2 x^2}}\right )}{3 e^3 \sqrt {-c^2 x^2}}\\ \end {align*}
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Mathematica [A]
time = 1.16, size = 241, normalized size = 0.96 \begin {gather*} \frac {b c d e \sqrt {1+\frac {1}{c^2 x^2}} x \left (d+e x^2\right )+a \left (c^2 d-e\right ) \left (8 d^2+12 d e x^2+3 e^2 x^4\right )+b \left (c^2 d-e\right ) \left (8 d^2+12 d e x^2+3 e^2 x^4\right ) \text {csch}^{-1}(c x)}{3 \left (c^2 d-e\right ) e^3 \left (d+e x^2\right )^{3/2}}-\frac {b \sqrt {1+\frac {1}{c^2 x^2}} x \left (8 c \sqrt {d} \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {1+c^2 x^2}}{\sqrt {d+e x^2}}\right )-3 \sqrt {e} \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {1+c^2 x^2}}{c \sqrt {d+e x^2}}\right )\right )}{3 e^3 \sqrt {1+c^2 x^2}} \end {gather*}
Antiderivative was successfully verified.
[In]
Integrate[(x^5*(a + b*ArcCsch[c*x]))/(d + e*x^2)^(5/2),x]
[Out]
(b*c*d*e*Sqrt[1 + 1/(c^2*x^2)]*x*(d + e*x^2) + a*(c^2*d - e)*(8*d^2 + 12*d*e*x^2 + 3*e^2*x^4) + b*(c^2*d - e)*
(8*d^2 + 12*d*e*x^2 + 3*e^2*x^4)*ArcCsch[c*x])/(3*(c^2*d - e)*e^3*(d + e*x^2)^(3/2)) - (b*Sqrt[1 + 1/(c^2*x^2)
]*x*(8*c*Sqrt[d]*ArcTanh[(Sqrt[d]*Sqrt[1 + c^2*x^2])/Sqrt[d + e*x^2]] - 3*Sqrt[e]*ArcTanh[(Sqrt[e]*Sqrt[1 + c^
2*x^2])/(c*Sqrt[d + e*x^2])]))/(3*e^3*Sqrt[1 + c^2*x^2])
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Maple [F]
time = 0.12, size = 0, normalized size = 0.00 \[\int \frac {x^{5} \left (a +b \,\mathrm {arccsch}\left (c x \right )\right )}{\left (e \,x^{2}+d \right )^{\frac {5}{2}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(x^5*(a+b*arccsch(c*x))/(e*x^2+d)^(5/2),x)
[Out]
int(x^5*(a+b*arccsch(c*x))/(e*x^2+d)^(5/2),x)
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x^5*(a+b*arccsch(c*x))/(e*x^2+d)^(5/2),x, algorithm="maxima")
[Out]
1/3*(3*x^4*e^(-1)/(x^2*e + d)^(3/2) + 12*d*x^2*e^(-2)/(x^2*e + d)^(3/2) + 8*d^2*e^(-3)/(x^2*e + d)^(3/2))*a +
1/3*b*((3*x^4*e^2 + 12*d*x^2*e + 8*d^2)*log(sqrt(c^2*x^2 + 1) + 1)/((x^2*e^4 + d*e^3)*sqrt(x^2*e + d)) + 3*int
egrate(1/3*(3*c^2*x^5*e^2 + 12*c^2*d*x^3*e + 8*c^2*d^2*x)/((c^2*x^4*e^4 + (c^2*d*e^3 + e^4)*x^2 + d*e^3)*sqrt(
c^2*x^2 + 1)*sqrt(x^2*e + d) + (c^2*x^4*e^4 + (c^2*d*e^3 + e^4)*x^2 + d*e^3)*sqrt(x^2*e + d)), x) - 3*integrat
e(1/3*(3*c^2*x^7*(log(c) + 1)*e^3 + 20*c^2*d^2*x^3*e + 8*c^2*d^3*x + 3*(5*c^2*d*e^2 + e^3*log(c))*x^5 + 3*(c^2
*x^7*e^3 + x^5*e^3)*log(x))/((c^2*x^6*e^5 + (2*c^2*d*e^4 + e^5)*x^4 + (c^2*d^2*e^3 + 2*d*e^4)*x^2 + d^2*e^3)*s
qrt(x^2*e + d)), x))
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 1531 vs.
\(2 (213) = 426\).
time = 0.64, size = 3102, normalized size = 12.36 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x^5*(a+b*arccsch(c*x))/(e*x^2+d)^(5/2),x, algorithm="fricas")
[Out]
[1/12*(3*(b*x^4*cosh(1)^3 + b*x^4*sinh(1)^3 - b*c^2*d^3 - (b*c^2*d*x^4 - 2*b*d*x^2)*cosh(1)^2 - (b*c^2*d*x^4 -
3*b*x^4*cosh(1) - 2*b*d*x^2)*sinh(1)^2 - (2*b*c^2*d^2*x^2 - b*d^2)*cosh(1) - (2*b*c^2*d^2*x^2 - 3*b*x^4*cosh(
1)^2 - b*d^2 + 2*(b*c^2*d*x^4 - 2*b*d*x^2)*cosh(1))*sinh(1))*sqrt(cosh(1) + sinh(1))*log(c^4*d^2 + (8*c^4*x^4
+ 8*c^2*x^2 + 1)*cosh(1)^2 + (8*c^4*x^4 + 8*c^2*x^2 + 1)*sinh(1)^2 + 4*(c^4*d*x + (2*c^4*x^3 + c^2*x)*cosh(1)
+ (2*c^4*x^3 + c^2*x)*sinh(1))*sqrt(x^2*cosh(1) + x^2*sinh(1) + d)*sqrt((c^2*x^2 + 1)/(c^2*x^2))*sqrt(cosh(1)
+ sinh(1)) + 2*(4*c^4*d*x^2 + 3*c^2*d)*cosh(1) + 2*(4*c^4*d*x^2 + 3*c^2*d + (8*c^4*x^4 + 8*c^2*x^2 + 1)*cosh(1
))*sinh(1)) + 4*(3*b*c*x^4*cosh(1)^3 + 3*b*c*x^4*sinh(1)^3 - 8*b*c^3*d^3 - 3*(b*c^3*d*x^4 - 4*b*c*d*x^2)*cosh(
1)^2 - 3*(b*c^3*d*x^4 - 3*b*c*x^4*cosh(1) - 4*b*c*d*x^2)*sinh(1)^2 - 4*(3*b*c^3*d^2*x^2 - 2*b*c*d^2)*cosh(1) -
(12*b*c^3*d^2*x^2 - 9*b*c*x^4*cosh(1)^2 - 8*b*c*d^2 + 6*(b*c^3*d*x^4 - 4*b*c*d*x^2)*cosh(1))*sinh(1))*sqrt(x^
2*cosh(1) + x^2*sinh(1) + d)*log((c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) + 1)/(c*x)) + 8*(b*c*x^4*cosh(1)^3 + b*c*x
^4*sinh(1)^3 - b*c^3*d^3 - (b*c^3*d*x^4 - 2*b*c*d*x^2)*cosh(1)^2 - (b*c^3*d*x^4 - 3*b*c*x^4*cosh(1) - 2*b*c*d*
x^2)*sinh(1)^2 - (2*b*c^3*d^2*x^2 - b*c*d^2)*cosh(1) - (2*b*c^3*d^2*x^2 - 3*b*c*x^4*cosh(1)^2 - b*c*d^2 + 2*(b
*c^3*d*x^4 - 2*b*c*d*x^2)*cosh(1))*sinh(1))*sqrt(d)*log((c^4*d^2*x^4 + 8*c^2*d^2*x^2 + x^4*cosh(1)^2 + x^4*sin
h(1)^2 - 4*(c^3*d*x^3 + c*x^3*cosh(1) + c*x^3*sinh(1) + 2*c*d*x)*sqrt(x^2*cosh(1) + x^2*sinh(1) + d)*sqrt(d)*s
qrt((c^2*x^2 + 1)/(c^2*x^2)) + 8*d^2 + 2*(3*c^2*d*x^4 + 4*d*x^2)*cosh(1) + 2*(3*c^2*d*x^4 + x^4*cosh(1) + 4*d*
x^2)*sinh(1))/x^4) + 4*(3*a*c*x^4*cosh(1)^3 + 3*a*c*x^4*sinh(1)^3 - 8*a*c^3*d^3 - 3*(a*c^3*d*x^4 - 4*a*c*d*x^2
)*cosh(1)^2 - 3*(a*c^3*d*x^4 - 3*a*c*x^4*cosh(1) - 4*a*c*d*x^2)*sinh(1)^2 - 4*(3*a*c^3*d^2*x^2 - 2*a*c*d^2)*co
sh(1) - (12*a*c^3*d^2*x^2 - 9*a*c*x^4*cosh(1)^2 - 8*a*c*d^2 + 6*(a*c^3*d*x^4 - 4*a*c*d*x^2)*cosh(1))*sinh(1) -
(b*c^2*d*x^3*cosh(1)^2 + b*c^2*d*x^3*sinh(1)^2 + b*c^2*d^2*x*cosh(1) + (2*b*c^2*d*x^3*cosh(1) + b*c^2*d^2*x)*
sinh(1))*sqrt((c^2*x^2 + 1)/(c^2*x^2)))*sqrt(x^2*cosh(1) + x^2*sinh(1) + d))/(c*x^4*cosh(1)^6 + c*x^4*sinh(1)^
6 - c^3*d^3*cosh(1)^3 - (c^3*d*x^4 - 2*c*d*x^2)*cosh(1)^5 - (c^3*d*x^4 - 6*c*x^4*cosh(1) - 2*c*d*x^2)*sinh(1)^
5 - (2*c^3*d^2*x^2 - c*d^2)*cosh(1)^4 - (2*c^3*d^2*x^2 - 15*c*x^4*cosh(1)^2 - c*d^2 + 5*(c^3*d*x^4 - 2*c*d*x^2
)*cosh(1))*sinh(1)^4 + (20*c*x^4*cosh(1)^3 - c^3*d^3 - 10*(c^3*d*x^4 - 2*c*d*x^2)*cosh(1)^2 - 4*(2*c^3*d^2*x^2
- c*d^2)*cosh(1))*sinh(1)^3 + (15*c*x^4*cosh(1)^4 - 3*c^3*d^3*cosh(1) - 10*(c^3*d*x^4 - 2*c*d*x^2)*cosh(1)^3
- 6*(2*c^3*d^2*x^2 - c*d^2)*cosh(1)^2)*sinh(1)^2 + (6*c*x^4*cosh(1)^5 - 3*c^3*d^3*cosh(1)^2 - 5*(c^3*d*x^4 - 2
*c*d*x^2)*cosh(1)^4 - 4*(2*c^3*d^2*x^2 - c*d^2)*cosh(1)^3)*sinh(1)), 1/12*(16*(b*c*x^4*cosh(1)^3 + b*c*x^4*sin
h(1)^3 - b*c^3*d^3 - (b*c^3*d*x^4 - 2*b*c*d*x^2)*cosh(1)^2 - (b*c^3*d*x^4 - 3*b*c*x^4*cosh(1) - 2*b*c*d*x^2)*s
inh(1)^2 - (2*b*c^3*d^2*x^2 - b*c*d^2)*cosh(1) - (2*b*c^3*d^2*x^2 - 3*b*c*x^4*cosh(1)^2 - b*c*d^2 + 2*(b*c^3*d
*x^4 - 2*b*c*d*x^2)*cosh(1))*sinh(1))*sqrt(-d)*arctan(1/2*(c^3*d*x^3 + c*x^3*cosh(1) + c*x^3*sinh(1) + 2*c*d*x
)*sqrt(x^2*cosh(1) + x^2*sinh(1) + d)*sqrt(-d)*sqrt((c^2*x^2 + 1)/(c^2*x^2))/(c^2*d^2*x^2 + d^2 + (c^2*d*x^4 +
d*x^2)*cosh(1) + (c^2*d*x^4 + d*x^2)*sinh(1))) + 3*(b*x^4*cosh(1)^3 + b*x^4*sinh(1)^3 - b*c^2*d^3 - (b*c^2*d*
x^4 - 2*b*d*x^2)*cosh(1)^2 - (b*c^2*d*x^4 - 3*b*x^4*cosh(1) - 2*b*d*x^2)*sinh(1)^2 - (2*b*c^2*d^2*x^2 - b*d^2)
*cosh(1) - (2*b*c^2*d^2*x^2 - 3*b*x^4*cosh(1)^2 - b*d^2 + 2*(b*c^2*d*x^4 - 2*b*d*x^2)*cosh(1))*sinh(1))*sqrt(c
osh(1) + sinh(1))*log(c^4*d^2 + (8*c^4*x^4 + 8*c^2*x^2 + 1)*cosh(1)^2 + (8*c^4*x^4 + 8*c^2*x^2 + 1)*sinh(1)^2
+ 4*(c^4*d*x + (2*c^4*x^3 + c^2*x)*cosh(1) + (2*c^4*x^3 + c^2*x)*sinh(1))*sqrt(x^2*cosh(1) + x^2*sinh(1) + d)*
sqrt((c^2*x^2 + 1)/(c^2*x^2))*sqrt(cosh(1) + sinh(1)) + 2*(4*c^4*d*x^2 + 3*c^2*d)*cosh(1) + 2*(4*c^4*d*x^2 + 3
*c^2*d + (8*c^4*x^4 + 8*c^2*x^2 + 1)*cosh(1))*sinh(1)) + 4*(3*b*c*x^4*cosh(1)^3 + 3*b*c*x^4*sinh(1)^3 - 8*b*c^
3*d^3 - 3*(b*c^3*d*x^4 - 4*b*c*d*x^2)*cosh(1)^2 - 3*(b*c^3*d*x^4 - 3*b*c*x^4*cosh(1) - 4*b*c*d*x^2)*sinh(1)^2
- 4*(3*b*c^3*d^2*x^2 - 2*b*c*d^2)*cosh(1) - (12*b*c^3*d^2*x^2 - 9*b*c*x^4*cosh(1)^2 - 8*b*c*d^2 + 6*(b*c^3*d*x
^4 - 4*b*c*d*x^2)*cosh(1))*sinh(1))*sqrt(x^2*cosh(1) + x^2*sinh(1) + d)*log((c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2))
+ 1)/(c*x)) + 4*(3*a*c*x^4*cosh(1)^3 + 3*a*c*x^4*sinh(1)^3 - 8*a*c^3*d^3 - 3*(a*c^3*d*x^4 - 4*a*c*d*x^2)*cosh
(1)^2 - 3*(a*c^3*d*x^4 - 3*a*c*x^4*cosh(1) - 4*a*c*d*x^2)*sinh(1)^2 - 4*(3*a*c^3*d^2*x^2 - 2*a*c*d^2)*cosh(1)
- (12*a*c^3*d^2*x^2 - 9*a*c*x^4*cosh(1)^2 - 8*a*c*d^2 + 6*(a*c^3*d*x^4 - 4*a*c*d*x^2)*cosh(1))*sinh(1) - (b*c^
2*d*x^3*cosh(1)^2 + b*c^2*d*x^3*sinh(1)^2 + b*c^2*d^2*x*cosh(1) + (2*b*c^2*d*x^3*cosh(1) + b*c^2*d^2*x)*sinh(1
))*sqrt((c^2*x^2 + 1)/(c^2*x^2)))*sqrt(x^2*cosh(1) + x^2*sinh(1) + d))/(c*x^4*cosh(1)^6 + c*x^4*sinh(1)^6 - c^
3*d^3*cosh(1)^3 - (c^3*d*x^4 - 2*c*d*x^2)*cosh(...
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x**5*(a+b*acsch(c*x))/(e*x**2+d)**(5/2),x)
[Out]
Timed out
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(x^5*(a+b*arccsch(c*x))/(e*x^2+d)^(5/2),x, algorithm="giac")
[Out]
integrate((b*arccsch(c*x) + a)*x^5/(e*x^2 + d)^(5/2), x)
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x^5\,\left (a+b\,\mathrm {asinh}\left (\frac {1}{c\,x}\right )\right )}{{\left (e\,x^2+d\right )}^{5/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
int((x^5*(a + b*asinh(1/(c*x))))/(d + e*x^2)^(5/2),x)
[Out]
int((x^5*(a + b*asinh(1/(c*x))))/(d + e*x^2)^(5/2), x)
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